bc518174
 王天杨
提交两个项目文件
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import number from "./number.js";
var reA = /[-+]?(?:\d+\.?\d*|\.?\d+)(?:[eE][-+]?\d+)?/g,
reB = new RegExp(reA.source, "g");
function zero(b) {
return function() {
return b;
};
}
function one(b) {
return function(t) {
return b(t) + "";
};
}
export default function(a, b) {
var bi = reA.lastIndex = reB.lastIndex = 0, // scan index for next number in b
am, // current match in a
bm, // current match in b
bs, // string preceding current number in b, if any
i = -1, // index in s
s = [], // string constants and placeholders
q = []; // number interpolators
// Coerce inputs to strings.
a = a + "", b = b + "";
// Interpolate pairs of numbers in a & b.
while ((am = reA.exec(a))
&& (bm = reB.exec(b))) {
if ((bs = bm.index) > bi) { // a string precedes the next number in b
bs = b.slice(bi, bs);
if (s[i]) s[i] += bs; // coalesce with previous string
else s[++i] = bs;
}
if ((am = am[0]) === (bm = bm[0])) { // numbers in a & b match
if (s[i]) s[i] += bm; // coalesce with previous string
else s[++i] = bm;
} else { // interpolate non-matching numbers
s[++i] = null;
q.push({i: i, x: number(am, bm)});
}
bi = reB.lastIndex;
}
// Add remains of b.
if (bi < b.length) {
bs = b.slice(bi);
if (s[i]) s[i] += bs; // coalesce with previous string
else s[++i] = bs;
}
// Special optimization for only a single match.
// Otherwise, interpolate each of the numbers and rejoin the string.
return s.length < 2 ? (q[0]
? one(q[0].x)
: zero(b))
: (b = q.length, function(t) {
for (var i = 0, o; i < b; ++i) s[(o = q[i]).i] = o.x(t);
return s.join("");
});
}
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