bc518174
 王天杨
提交两个项目文件
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"use strict";
Object.defineProperty(exports, "__esModule", {
value: true
});
exports.getEquidistantTicks = getEquidistantTicks;
var _TickUtils = require("../util/TickUtils");
var _getEveryNthWithCondition = require("../util/getEveryNthWithCondition");
function getEquidistantTicks(sign, boundaries, getTickSize, ticks, minTickGap) {
var result = (ticks || []).slice();
var initialStart = boundaries.start,
end = boundaries.end;
var index = 0;
// Premature optimisation idea 1: Estimate a lower bound, and start from there.
// For now, start from every tick
var stepsize = 1;
var start = initialStart;
var _loop = function _loop() {
// Given stepsize, evaluate whether every stepsize-th tick can be shown.
// If it can not, then increase the stepsize by 1, and try again.
var entry = ticks === null || ticks === void 0 ? void 0 : ticks[index];
// Break condition - If we have evaluate all the ticks, then we are done.
if (entry === undefined) {
return {
v: (0, _getEveryNthWithCondition.getEveryNthWithCondition)(ticks, stepsize)
};
}
// Check if the element collides with the next element
var i = index;
var size;
var getSize = function getSize() {
if (size === undefined) {
size = getTickSize(entry, i);
}
return size;
};
var tickCoord = entry.coordinate;
// We will always show the first tick.
var isShow = index === 0 || (0, _TickUtils.isVisible)(sign, tickCoord, getSize, start, end);
if (!isShow) {
// Start all over with a larger stepsize
index = 0;
start = initialStart;
stepsize += 1;
}
if (isShow) {
// If it can be shown, update the start
start = tickCoord + sign * (getSize() / 2 + minTickGap);
index += stepsize;
}
},
_ret;
while (stepsize <= result.length) {
_ret = _loop();
if (_ret) return _ret.v;
}
return [];
}
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